# coding: utf-8 # # Checking Rank Estimates # In[29]: import numpy as np import numpy.linalg as la import matplotlib.pyplot as pt # Let's make two particle collections: sources and targets # In[8]: sources = np.random.randn(2, 200) targets = np.random.randn(2, 200) + 10 pt.plot(sources[0], sources[1], "go") pt.plot(targets[0], targets[1], "ro") # What's our convergence ratio $\rho$: # $$# \rho=\frac{d(c,\text{furthest target})}{d(c,\text{closest source})}? #$$ # # Well, what should $c$ be, really? (Technically, we can use any $c$, so we're free to choose whichever we think is best.) # In[21]: c = np.sum(targets, axis=1) / targets.shape[1] c # In[22]: pt.plot(sources[0], sources[1], "go") pt.plot(targets[0], targets[1], "ro") pt.plot(c[0], c[1], "bo") # ## Assemble the interaction matrix # In[24]: all_distvecs = sources.reshape(2, 1, -1) - targets.reshape(2, -1, 1) dists = np.sqrt(np.sum(all_distvecs**2, axis=0)) interaction_mat = np.log(dists) # ## Estimate the rank depending on precision $\varepsilon$ # First, obtain an idea of what $\rho$ is: # In[28]: dist_tgt_to_c = np.sqrt(np.sum((c.reshape(2, 1) - targets)**2, axis=0)) dist_src_to_c = np.sqrt(np.sum((c.reshape(2, 1) - sources)**2, axis=0)) rho = np.max(dist_tgt_to_c) / np.min(dist_src_to_c) rho # Then plot the numerical rank depending on epsilon: # In[33]: _, sigma, V = la.svd(interaction_mat) pt.semilogy(sigma) # In[40]: eps_values = 10**(-np.linspace(1, 12)) # For the given precisions $\varepsilon$, find the associated numerical rank: # In[42]: def numrank(eps): return np.sum(sigma > eps) ranks = [numrank(e) for e in eps_values] pt.semilogx(eps_values, ranks) # Now compare with our estimate: # In[38]: pt.semilogx(eps_values, ranks) pt.semilogx(eps_values, (np.log(eps_values)/np.log(rho)-1)**2) # * We estimated that the rank would grow *quadratically*. # * Comments on how good our estimate is?